(x+8)^2=81
Thank you so much
Please help me solve my using the square root property.?
2007-12-26 5:17 pm
回答 (10)
2007-12-26 5:22 pm
✔ 最佳答案
sqrt(x+8)^2 = sqrt(81)x+8 =9
x=1
2007-12-30 8:53 am
x + 8 = ± 9
x = 1 , x = - 17
x = 1 , x = - 17
2007-12-26 5:27 pm
x^2+16x+64=81
x^2+16x-17=0
x^2+17x-x-17=0
x(x+17)-1(x+17)=0
(x+17)(x-1)=0
x=1 or x=-17
x^2+16x-17=0
x^2+17x-x-17=0
x(x+17)-1(x+17)=0
(x+17)(x-1)=0
x=1 or x=-17
2007-12-27 12:24 am
x+8)² = 81
If we notice|fix (x+8)², of a remarkable product or also enumenat remarkable formula, which he|she|it says: The square of the sum of two numbers him equal to|in the square of the first, more the double of
frequents the first for the second, more the square of the second.
Therefore:
x² + 2x(8) + 8² = 81
x² + 16x +64 = 81
x² + 16x + 64 - 81= 0
x² + 16x - 17= 0
This qu once solved by the usual procedure is a quadratic equation,
it faces|gives:
x' = 1
x" = -17
Greetings from Catalonia and until the next one
Good Christmas
If we notice|fix (x+8)², of a remarkable product or also enumenat remarkable formula, which he|she|it says: The square of the sum of two numbers him equal to|in the square of the first, more the double of
frequents the first for the second, more the square of the second.
Therefore:
x² + 2x(8) + 8² = 81
x² + 16x +64 = 81
x² + 16x + 64 - 81= 0
x² + 16x - 17= 0
This qu once solved by the usual procedure is a quadratic equation,
it faces|gives:
x' = 1
x" = -17
Greetings from Catalonia and until the next one
Good Christmas
2007-12-26 5:26 pm
(x+8)² = 81
x + 8 = â81
x + 8 = ±9
Remember for a quadratic equation there are two roots, since the square root of 81 is positive or negative 9 you have two real solutions.
x = -9 -8 = -17
x = 9 -8 = 1
x + 8 = â81
x + 8 = ±9
Remember for a quadratic equation there are two roots, since the square root of 81 is positive or negative 9 you have two real solutions.
x = -9 -8 = -17
x = 9 -8 = 1
2007-12-26 5:28 pm
Step one: Take the square root of both sides. You will get:
x+8=9 OR x+8=-9, because 9^2 is 81, and so is (-9)^2.
Step two: Subtract 8 from both sides.
You get x=1 or x=-17
Hope I helped!!
:o)
x+8=9 OR x+8=-9, because 9^2 is 81, and so is (-9)^2.
Step two: Subtract 8 from both sides.
You get x=1 or x=-17
Hope I helped!!
:o)
2007-12-26 5:25 pm
(x+8)^2 = 81
taking sq rt from both side
x+8 = 9 or x+8 = -9
x = 1 or x = -17
taking sq rt from both side
x+8 = 9 or x+8 = -9
x = 1 or x = -17
2007-12-26 6:48 pm
(x+8)*2=9*2
x=1
x=1
2007-12-26 5:34 pm
x^2+2*x*8+64=81
x^2+16*x=17
x^2+16*x-17=0
D=b^2-4*a*g
=256-4*1*(-17)
=256-68
=188>0
X 1,2= -b + / - D
= -16 + / - (root of number 188)
x^2+16*x=17
x^2+16*x-17=0
D=b^2-4*a*g
=256-4*1*(-17)
=256-68
=188>0
X 1,2= -b + / - D
= -16 + / - (root of number 188)
2007-12-26 5:23 pm
(x + 8)^2 = 81
x + 8 = â81
x + 8 = 9
x = 9 - 8
x = 1
x + 8 = â81
x + 8 = 9
x = 9 - 8
x = 1
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