F.3 Maths

2007-12-27 3:41 am
Factorize :
1. -mn(ax+b) - (m)(m)(n)(ax+b)
2. (-a+b)(x-y) - (a+b) (x-y)
3. 5(x-y)(x-y)(x-y) - 10 (y-x)(y-x)
4. (2b-c)[(x)(x)+2] + (c-2b)[2-(x)(x)]
5. (4h-6k)(4h-6k) + 3k - 2h

回答 (1)

2007-12-27 4:15 am
✔ 最佳答案
Factorize :
1. -mn(ax+b) - (m)(m)(n)(ax+b)
= -mn(ax+b) - (m)(mn)(ax+b)
= -mn(ax+b)(1+m)

2. (-a+b)(x-y) - (a+b) (x-y)
=(x-y)[ (-a+b)- a-b)]
=(x-y)(-2a)
=-2a(x-y)

3. 5(x-y)(x-y)(x-y) - 10 (y-x)(y-x)
=5(x-y)^3 - 10 (y-x)^2
=5(x-y)^3 - 10 (x-y)^2
=5[(x-y) - 2](x-y)^2
=5(x-y - 2)(x-y)^2

4. (2b-c)[(x)(x)+2] + (c-2b)[2-(x)(x)]
= (2b-c)(x^2+2) - (2b-c)(2-x^2)
= (2b-c)[(x^2+2) - (2-x^2)]
= (2b-c)[(x^2+2) - 2+x^2]
= (2b-c)[2x^2]
= 2x^2(2b-c)

5. (4h-6k)(4h-6k) + 3k - 2h
= 4(2h-3k)(2h-3k) + 3k - 2h
= 4(2h-3k)^2 - (2h-3k)
= (2h-3k)[4(2h-3k)-1]
= (2h-3k)(8h-12k-1)




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