1)p^-2
----------
p^-4?
2)(5x^2)^2
------------
(x^2)^3
3)(y^2
--------
z^4)^3
小算盤有冇得計[^]ga?
教下我做..
數學數學!!!!!!!
2007-12-27 1:37 am
回答 (2)
2007-12-27 1:54 am
✔ 最佳答案
1.P^-2/P^-4=P^4/P^2
=P^2
2)(5x^2)^2/(x^2)^3
=25x^4/x^6
=25/x^2
3)(y^2)/(z^4)^3
=y^2/z^12
小算盤有得計[^]
but要係小算盤個檢視度禁工程型
咁就有x^2,,x^3,,x^y個d制出現係左邊嫁啦
2007-12-27 7:44 pm
1)
p^-2
----------
p^-4
= p^﹝-2-(-4)﹞.....除號係 - ,所以指數係-2-(-4)
= p^-2+4
= p^2
2)
(5x^2)^2
------------
(x^2)^3
= 25x^4 / x^6
= 25x^(4-6) ....25係整數 ,同x既指數無關 <---要注意!
= 25x^-2 .....x既指數有負數一定要變分母 ,如果唔係答案就唔係化到最簡
= 25 /x^2
3)
y^2
--------
(z^4)^3
= y^2/z^12 ....有( )既指數就要乘
p^-2
----------
p^-4
= p^﹝-2-(-4)﹞.....除號係 - ,所以指數係-2-(-4)
= p^-2+4
= p^2
2)
(5x^2)^2
------------
(x^2)^3
= 25x^4 / x^6
= 25x^(4-6) ....25係整數 ,同x既指數無關 <---要注意!
= 25x^-2 .....x既指數有負數一定要變分母 ,如果唔係答案就唔係化到最簡
= 25 /x^2
3)
y^2
--------
(z^4)^3
= y^2/z^12 ....有( )既指數就要乘
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