Y除２-４Y除５＝２
Y＝幾？
要列式
幫我!!!!!~~數學~
2007-12-26 2:36 am
回答 (6)
2007-12-26 2:42 am
✔ 最佳答案
(5y-8y)/10=2-3y=20
y=-20/3
2007-12-26 4:47 am
Y除２-４Y除５＝２
=> (Y/2) - (4Y/5) = 2
=> 10 x (Y/2) - 10 x (4Y/5) = 10 x 2
=> 5Y - 8Y = 20
=> -3Y = 20
=> Y = -20/3
=> (Y/2) - (4Y/5) = 2
=> 10 x (Y/2) - 10 x (4Y/5) = 10 x 2
=> 5Y - 8Y = 20
=> -3Y = 20
=> Y = -20/3
2007-12-26 2:54 am
y/2 - 4y/5 = 2
5y/10 - 8y/10 = 2
-3y = 20
y = -6又3分之2
5y/10 - 8y/10 = 2
-3y = 20
y = -6又3分之2
2007-12-26 2:44 am
y/2-4y/5=2
5y-8y=20
y=-20/3
5y-8y=20
y=-20/3
2007-12-26 2:44 am
Y/2-4Y/5＝2
Y(5)-4Y(2) / 10 =2 先通分
5Y-8Y /10 = 2 乘埋啦
-3Y = 20 10 移位
Y= - 20/3 KO ANS= 負3分之二十
Y(5)-4Y(2) / 10 =2 先通分
5Y-8Y /10 = 2 乘埋啦
-3Y = 20 10 移位
Y= - 20/3 KO ANS= 負3分之二十
收錄日期: 2021-04-23 19:47:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071225000051KK02749