10(a+2)+5(a+2)(a+2)
= ???
= ???
= ???
= ???
=5(a+2)(a+4)
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f2maths {factorize}急急急 10點
2007-12-25 11:31 pm
回答 (2)
2007-12-25 11:37 pm
✔ 最佳答案
10(a+2)+5(a+2)(a+2)= 5(a+2)(2+a+2)
= 5(a+2)(a+4)
There are two terms:
10(a+2) and 5(a+2)(a+2)
There is one common factor:
5(a+2)
10(a+2)/5(a+2) = 2
5(a+2)(a+2)/5(a+2) = a+2
2007-12-25 11:59 pm
The answer is ......
10(a+2)+5(a+2)(a+2)
= 5(a+2)(2+a+2)
= 5(a+2)(a+4)
There are two terms:
10(a+2) and 5(a+2)(a+2)
There is one common factor:
5(a+2)
10(a+2)/5(a+2) = 2
5(a+2)(a+2)/5(a+2) = a+2
10(a+2)+5(a+2)(a+2)
= 5(a+2)(2+a+2)
= 5(a+2)(a+4)
There are two terms:
10(a+2) and 5(a+2)(a+2)
There is one common factor:
5(a+2)
10(a+2)/5(a+2) = 2
5(a+2)(a+2)/5(a+2) = a+2
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