How to write the number 95 in Roman Numeral? Is it VL or XLV?

XCV = 95
XCIX = 99

C is 100. L =50 X= 10 V=5 I=1

the number in front is subtracted from larger numbers behind and added to smaller numbers. only 3 of a number. if you need 4 go to the subtraction rule

The site below gives a full explanation.

I=1 , V=5 , X=10 , L=50 , C=100 , D=500 , M=1000

95 = VC (100-5)
99 = IC (100-1)

When the small Roman Numeral (e.g. X) is on the left hand side of the big Roman Numeral (e.g. D) , that means the relation of them is to subtract the small Roman Numeral from the big Roman Numeral:
XD = 490 (500-10)

95 = 90+5 and so is written ax XCV, since XC is 90 and V is 5

99=90+9 so this is XC (90) IX(9) or XCIX

95 is XCV

100 - 10 + 5 = 95

99 is XCIX

100 - 10 + 9 = 99

95 In Roman Numerals

L = 50 X = 10 C = 100 LXXX = 80 XC = 90

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RE:
How to write the number 95 in Roman Numeral? Is it VL or XLV?
How abt 99? is IL or XLIX? what is the rule if its so?

VC doesn't exist.
C= 100
X = 10
V= 5
XC = 90 = 100 -10
XCV = 95 = 100-10 + 5

L = 50
VL doesn't exist.
XLV? XL = 50 -10 = 40, therefore XLV = 40 +5 = 45.
IL? Doesn't exist.
XLIX = 49

LXL = 50 + 10 + 50 so it doesn't equal 90! It equals 110!

99 = 90+9 = (100 -10 ) + 9 = XCIX.
LXLV = 50 + 10 + 50 + 5 = 115, not 95!

I=1, V=5, X=10, L=50, C=100, D=500, M=1,000
I, X, and M can usually be repeated up to 3 times in succession, so III=3, XXX=30, and MMM=3,000.
To write other values, place a smaller numeral before a larger to subtract it: IV=4, IX=9, XIX=19, XL=40, and LXL=90.
Placing a smaller after a larger adds it, so VI=6, XI=11, XXI=21, XLV=45, and LXLV=95.

VC=95
IC=99