因式分解 連列式

(b+a)^2-ap-bp
=(a+b)^2-p(a+b)
=(a+b)(a+b-p)

64(a+b)^2-(b-a)^2
=64a^2+128ab+64b^2 -b^2+2ab-a^2
=63a^2+130ab+63b^2
=(7a+9b)(9a+7b)

2-18(a+1)^2
=2-18a^2-36a-18
=-18a^2-36a-16
=-2(9a^2+18a+8)
=-2(3a+4)(3a+2)

m(x+y)^2-4m(x-y)^2
=mx^2+2mxy+my^2 - 4mx^2+8mxy-4my^2
=-3mx^2+10mxy-3my^2
=-m(3x-y)(x-3y)

25m^2 +4n^2 +20mn
=25m^2+20mn+4n^2
=(5m)^2+2(5m)(2n)+(2n)^2
=(5m+2n)^2

第１條 (b+a)2次方-ap-bp
=(a+b)2次方-ap-bp
=(a+b)2次方-p(a+b)
=(a+b)(a+b-p)

第３條 2-18(a+1)2次方
=2-18(a+1)(a+1)
=2-18(a 2次方+a+a+1 2次方)
=2-18(a 2次方+2a+1)
=2-18a 2次方-36a-18
=2(1-9a 2次方-18a-9)

2007-12-24 16:15:53 補充：
第5條 25m2次方 4n2次方 20mn =(5m)2次方 2(2n)(5m) (2n)2次方=(5m 2n)2次方