因式分解:
(x+3)^2-(x+1)(x-3)≡P(x+1)+Q
求P及Q.
Ans:P=8及Q=4
因式分解:(x+3)^2-(x+1)(x-3)≡P(x+1)+Q
2007-12-24 9:23 am
回答 (1)
2007-12-24 10:03 am
✔ 最佳答案
P(x+1)+Q≡(x+3)^2-(x+1)(x-3)P(x+1)+Q≡(x^2+6x+9)-(x^2-2x-3)
P(x+1)+Q≡x^2+6x+9-x^2+2x+3
P(x+1)+Q≡8x+12
P(x+1)+Q≡8x+8+4
P(x+1)+Q≡8(x+1)+4
Therefore P=8 and Q=4
收錄日期: 2021-04-13 19:12:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071224000051KK00347