MATHS!!

2007-12-23 7:15 am
教我simplify下列算式: [?]=幾次方
1. (3 x[2] - 5 y[2] ) - (6 y[2] - 2 z[2] ) + ( 7 z[2] + x[2] )
2. ( x + 3y - 4z ) + ( 5x -8y + z ) - ( 6x + 2y + z )
3. 4y + 5x - 8x - 4y + 7x + 3y
更新1:

可唔可以列清楚條式? 我唔係好明個答案點得黎!

更新2:

1. ... = 3 x[2] + x[2] - 5 y[2] - 6 y[2] + 2 z[2] + 7 z[2] + x[2] 呢條式之後係咪咁... = (3+1)x[2] - (5+6)y[2] + (2+7)z[2]

回答 (3)

2007-12-23 7:32 am
✔ 最佳答案
1.(3 x[2] - 5 y[2] ) - (6 y[2] - 2 z[2] ) + ( 7 z[2] + x[2] )
=3x[2] - 5y[2] - 6y[2] + 2z[2] + 7z[2] + x[2] <----拆括號
=3x[2] + x[2] - 5y[2] - 6y[2] + 2z[2] + 7z[2] <----把同類的數放在一起
=4x[2] - 11y[2] + 9z[2]

2.( x + 3y - 4z ) + ( 5x -8y + z ) - ( 6x + 2y + z )
=x + 3y - 4z + 5x - 8y + z - 6x - 2y - z
=x + 5x - 6x + 3y - 8y - 2y - 4z + z - z
= - 7y - 4z

3. 4y + 5x - 8x - 4y + 7x + 3y
=4y - 4y + 3y + 5x - 8x + 7x
=3y + 4x

同類的數eg. 5 and 8
eg1 5x and 8x
eg2 5x[2] and 8x[2] (次方必須一樣)
參考: 自己
2007-12-23 7:48 am
1. (3 x[2] - 5 y[2] ) - (6 y[2] - 2 z[2] ) + ( 7 z[2] + x[2] )
= 3x[2] - 5 y[2]- 6 y[2] + 2 z[2] + 7 z[2] + x[2]
=3x[2]+ x[2]- 5 y[2]- 6 y[2]+ 2 z[2] + 7 z[2]
=4x[2] -11y[2] + 9z[2]

2)( x + 3y - 4z ) + ( 5x -8y + z ) - ( 6x + 2y + z )
= x+3y - 4z + 5x - 8y +z -6x -2y -z
= x+5x-6x+3y - 8y -2y -4z + z -z
= -7y -4z

3) 4y + 5x - 8x - 4y + 7x + 3y
= 4y- 4y + 3y + 5x- 8x + 7x
= 3y + 4x

(其實做衣d數係有技巧嫁,開頭要拆哂d括號,要變符號就變哂先,跟張一d同類既野擺埋一齊,x還x擺,y還y擺,z還z擺,相加減就易得多又唔容易計錯,做完仲方便你核對你做得岩唔岩!另外開頭做可能會有d混亂or唔係好識計,所以除左有技巧外,做多d都係好要嫁!做熟d見多d題目,再遇到時候就諗得快d同做得快d嫁喇! 加油啦!)希望衣個方法幫到你啦!
參考: me
2007-12-23 7:26 am
1.
(3 x[2] - 5 y[2] ) - (6 y[2] - 2 z[2] ) + ( 7 z[2] + x[2] )
=3x^2-5y^2-6y^2+2z^2+7z^2+x^2
=4x^2-11y^2+9z^2+9

2.
( x + 3y - 4z ) + ( 5x -8y + z ) - ( 6x + 2y + z )
= x + 3y - 4z + 5x -8y + z - 6x- 2y - z
= -7y-4z

3.
4y + 5x - 8x - 4y + 7x + 3y
= 4x+3y


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