1.a shopkeeper buys 180 boxes of oranges.He throw away 1/5(5分之1) of them because they are bad.He sells 5/6(6分之5) of the remaining oranges at a profit of 35% on the original price. He sells the remaining 1/6(6分之1)(姐係180既5分之4既6分之1) at 20% profit on the original price.If the total price are $4770,find the profit% he made.
2.377 7/9%(三百七十七又九分之七%)(377又9分之7%)轉做小數= =
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2007-12-23 4:06 am
回答 (2)
2007-12-23 4:59 am
✔ 最佳答案
1 - 5/6 at 35% profit:(5/6)*(7/20)=7/24
1/6 at 20% profit:(1/6)*(1/5)
=1/30
the profit% he made:(7/24)+(1/30)
=13/40
=32.5%
So the profit% he made is 32.5%.
2 - 377 7/9% = 378.2857143
2007-12-23 4:50 am
1)Let x be the orginal pricefor each box.
4770=180*(1-1/5)*(5/6)*(1+35%)x+180*(1-1/5)*(1/6)*(1+20%)x
4770=162x+28.8x
4770=190.8x
x=25
∴the orginal price for each box is $25.
The profit% :
180*25-4770
------------------
180*25
=-0.06
=-6%
2)
.
3.77777777777(7為循環小數)
|-----------------|無限之多
4770=180*(1-1/5)*(5/6)*(1+35%)x+180*(1-1/5)*(1/6)*(1+20%)x
4770=162x+28.8x
4770=190.8x
x=25
∴the orginal price for each box is $25.
The profit% :
180*25-4770
------------------
180*25
=-0.06
=-6%
2)
.
3.77777777777(7為循環小數)
|-----------------|無限之多
收錄日期: 2021-04-25 22:21:19
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