✔ 最佳答案
y^12 - 4096
= (y^6)^2 - 64^2
= (y^6 - 64)(y^6 + 64)
= [ (y^3)^2 - 8^2 ] (y^6 + 64)
= (y^3 - 8)(y^3 + 8) (y^6 + 64)
= (y - 2)(y^2 + 2y + 4)(y^3 + 8) (y^6 + 64)
= (y - 2) (y^2 + 2y + 4) (y + 2) (y^2 - 2y + 4)(y^6 + 64)
= (y - 2) (y^2 + 2y + 4) (y + 2) (y^2 - 2y + 4) [(y^2)^3 + 4^3]
= (y - 2) (y^2 + 2y + 4) (y + 2) (y^2 - 2y + 4) (y^2 + 4)(y^4 - 4y^2 + 16)