what is the anser to 14=6(f+2)-2f?
回答 (7)
2007-12-24 7:45 pm
✔ 最佳答案
14 = 6f + 12 - 2f2 = 4f
f = ½
2007-12-22 9:51 am
14 = 6(f + 2) - 2f
14 = 6f + 12 - 2f
14 = 6f - 2f + 12
14 = 2f +12
2f = 14 - 12
2f = 2
2f/2 = 2/2
f = 1
14 = 6f + 12 - 2f
14 = 6f - 2f + 12
14 = 2f +12
2f = 14 - 12
2f = 2
2f/2 = 2/2
f = 1
2007-12-22 4:00 am
14=6(f+2)-2f
14=6f + 12 - 2f
14=4f + 12
14-12=4f + 12-12
2=4f
2/4 = 4/4 f
1/2 = f
14=6f + 12 - 2f
14=4f + 12
14-12=4f + 12-12
2=4f
2/4 = 4/4 f
1/2 = f
2007-12-22 4:00 am
14=6(f+2)-2f
14=6f+12-2f
14-12=4f+12-12
2=4f
2/4=f
1/2=f
14=6f+12-2f
14-12=4f+12-12
2=4f
2/4=f
1/2=f
2007-12-22 3:58 am
The answer is 1/2.
How to get to it:
1) Distribute 6 across (f+2)
2) Subtract 12 from both sides
3) Add like terms 6f-2f
4) Divide both sides by 4
How to get to it:
1) Distribute 6 across (f+2)
2) Subtract 12 from both sides
3) Add like terms 6f-2f
4) Divide both sides by 4
2007-12-22 3:57 am
I think the answer is 2/4.
2007-12-22 4:00 am
answer is f= -1/4
參考: 14=6(f+2)-2f=(do distubitive proberty)
14=6f+12-2f=(minus 6f by -2f)
14=-8f+12=(subtract 12 by 12 and 14)
2= -8f=(divide by -8 on both sides)
f= -1/4
收錄日期: 2021-05-01 01:21:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071221194742AAQ5z11