1. Subtract polynomials: [(3/7)x^3-(1/5)x-(1/3)]-[-(2/7)x^3+(1/4)x-(1/3)]
2. Use a vertical format to subtract the polynomials:
(3y^4-4y^2+7)-
(-5y^4-6y^2-13)
3. Find the product of: (x^2+2x+1)(x^2-x+2)
Math questions?
2007-12-19 2:30 pm
回答 (3)
2007-12-19 2:34 pm
✔ 最佳答案
If I don't do it, will I still pass the course?
2007-12-19 3:21 pm
I couldn't do #1 because it is incomplete. If you display it like #2 I believe I could solve it.
#2. ( 3y^4-4y^2+7)
-(-5y^4-6y^2-13)
= > 8y^4+2y^2+20
#3 (x^2+2x+1)(x^2-x+2)=x^4+x^3+x^2+3x+2
#2. ( 3y^4-4y^2+7)
-(-5y^4-6y^2-13)
= > 8y^4+2y^2+20
#3 (x^2+2x+1)(x^2-x+2)=x^4+x^3+x^2+3x+2
2007-12-19 2:47 pm
1. (5/7)x^3-(9/20)x
2. ( 3y^4-4y^2+ 7)
-) (-5y^4-6y^2-13)
---------------------------
8y^4+2y^2+20
3. (x^2+2x+1)(x^2-x+2)
=x^4-x^3+2x^2+2x^3-2x^2+4x+x^2-x+2
=x^4+x^3+x^2-5x+2
2. ( 3y^4-4y^2+ 7)
-) (-5y^4-6y^2-13)
---------------------------
8y^4+2y^2+20
3. (x^2+2x+1)(x^2-x+2)
=x^4-x^3+2x^2+2x^3-2x^2+4x+x^2-x+2
=x^4+x^3+x^2-5x+2
收錄日期: 2021-05-03 13:56:26
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