Form2 數學題 (15分)

2007-12-18 1:30 am
請解答以下數學題並詳細列出步驟:

Shan Shan starts off from city A and cycles at a speed of 100m/min towards city B. At the same time, Tze Ming and Siu Ying start off from city B and cycle towards city A at 80m/min and 75m/min respectively. If Shan Shan meets Siu Ying 6 minutes after she has met Tze Ming, find the distance (in km) between the cities A and B.

回答 (2)

2007-12-18 1:46 am
✔ 最佳答案
Shan Shan cycle from City A to City B at 100m/min
Tze Ming cycle from City B to City A at 80m/min
Siu Ying cycle from CIty B to City A at 75m/min

Let t be the time Shan Shan meets Tze Ming.
After t mins, Shan Shan cycled 100 x t =100t m
Tze Ming cycled 80 x t = 80t m
City A to B = 100t + 80t = 180t m --- (1)

Shan shan meets Siu Ying 6mins after Tze Ming = t + 6 mins
Shan Shan cycled 100 x (t + 6) = 100t + 600
Siu Ying cycled 75 x (t + 6) = 75t + 450
City A to B = 100t + 600 + 75t +450 = 175t + 1050 --- (2)

(1) = (2) ; 180t = 175t + 1050
5t = 1050
t = 1050 / 5 = 210 min

City A to B = 180t = 180 x 210 = 37800m = 37.8km
Checking 175 x 210 + 1050 = 37800m = 37.8km (ok)
2007-12-18 1:49 am
6分鐘之後Shan Shan踩左100x6=600米 
即距離city A 600米

而Siu Ying 踩左75x6=450米 
即距離city B 450米

因為佢地依家在同一點
所以佢地距離city A 600米
距離city B 450米

路全長 600+450=1050米
           =1.05公里


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