急!公式主項變換[重賞!!]

2007-12-16 11:07 pm
不懂得怎做-v-
請教一下

12. s等於ut加2分之1乘at的2次方 (主項變a)
13. v等於3分之1πr2次乘h (主項變h)
14. A等於πrL加πr2次 (主項變L)
15. v2次減u2次等於2as (主項變u)
16. p等於a加m over m減b (主項變m)

回答 (2)

2007-12-16 11:16 pm
✔ 最佳答案
12. s等於ut加2分之1乘at的2次方 (主項變a)
s = ut + at^2 / 2
s - ut = at^2 /2
2s - 2ut = at^2
2s - 2ut/ t^2 = a


13. v等於3分之1πr2次乘h (主項變h)
v = π r^2h /3
3v = π r^2h
3v / π r^2 = h

14. A等於πrL加πr2次 (主項變L)
A = πrL + πr^2
A - πr^2 / πr = L


15. v2次減u2次等於2as (主項變u)
v^2 - u^2 = 2as
v^2 - 2as = u^2
√(v^2 - 2as) = u

16. p等於a加m over m減b (主項變m)
p = a + m / m -b
p(m - b) = a + m
pm - pb = a + m
pm - m = a + pb
m(p- 1) = a + pb
m = a + pb / p-1
2007-12-16 11:20 pm
12)
s = ut +(1/2)at^2
(1/2)at^2 = s - ut
a = 2(S - ut) / (t^2)

13)
v = 1/3π(r^2)h
h = 3v/(πr^2)

14)
A =πr L + πr2
πr L = A - πr2
L = (A - πr2)/πr

15)
V^2 - u^2 = 2as
u^2 = v^2 - 2as
u = (v^2 - 2as)^(1/2)

16)
p = (a + m)/(m - b)
pm - pb = a + m
pm - m = a + pb
m(p-1) = a+ pb
m = (a + pb)/(p -1)
參考: 自己既運算


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