can anyone help me with 3x-5(6-2x)=4(x-8)+3?

3x - 30 + 10x = 4x - 32 + 3
13x - 30 = 4x - 29
9x = 1
x = 1 / 9

3x-5(6-2x) = 4(x-8)+3
3x-30+10x = 4x-32+3
13x-30 = 4x-29
13x-4x = 30-29
9x = 1
x = 1/9

3x-5(6-2x)=4(x-8)+3 <-- distributive property
3x -30+10x = 4x - 32 + 3 <-- collect like terms
13x - 30 = 4x - 29
9x = 1
x = 1/9

x=1/9

3x-30+10x= 4x -32+3.
9x= -32+3 +30=1. x=1/9.

3x-5(6-2x)=4(x-8)+3
3x-30+10x=4x-32+3
13x-30=4x-29
13x=4x+1
9x=1
x=1/9

What is your problem. First, you have to multiply the stuff in the two ( )by their respective coefficients. Then you move all the 'x' terms so they are on side of the equal sign and all the constants so they are on the other. Then you combine the terms on both sides by algebraic addition. Finally you have an equation Ax = B, so x= B/A. If you can't do these steps, better have a chat with your teacher.

3x-5(6-2x)=4(x-8)+3
3X-30+10X=4X-32+3
13x-30=4x-29
9x=1
x=1/9

3x-5(6-2x)=4(x-8)+3
3x-30+10x = 4x-32+3
3x+10x-4x = -32+3+30
9x = 1
9x/9 = 1/9
x = 1/9