化簡下列各式。
4/7x+1/7xy=?
k2次方/(m+4k)2次方 - 1/m+4k=?
中2-3級數學(化簡)
2007-12-15 8:09 pm
回答 (1)
2007-12-15 8:21 pm
✔ 最佳答案
^2 = 2次方 <------ 希望看得明# = 做完
4/7x+1/7xy
= (4) (1/7) x + (1/7) x y
= 1/7x (4 + y)
#
k ^2 / (m + 4k) ^2 - 1 / (m + 4k)
= k ^2 / (m + 4k) ^2 - (m + 4k) / (m + 4k) ^2 (通分母)
= [ k^2 - (m + 4k) ] / (m + 4k) ^2
= (k ^2 -4k -m) / (m + 4k) ^2
#
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071215000051KK01213