Very Very Very Easy Maths...

2007-12-15 12:52 am
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1)1+2+3+4+...+9+10=?
2)1+2+3+4+...+99+100=?
3)1+2+3+4+...+999+1000=?
4)1+2+3+4+...+9999+10000=?
5)1+2+3+4+...+9999+100000=?
6)1+2+3+4+...+99999+1000000=?
Quick......

回答 (6)

2007-12-15 1:02 am
✔ 最佳答案
By n(n+1)/2,

1) 10(10+1)/2 = 55

similarly,
2) 5050
3) 500500
4) 50005000
5) 5000050000
6) 500000500000
2007-12-16 5:36 am
1)55
2)5050
3)500500
4)50005000
5)5000050000
6)50000050000
2007-12-15 1:41 am
55
5505
Same...........
參考: 55
2007-12-15 1:20 am
1) 1+2+3+4+...+9+10
=10x11/2
=110/2
=55
2) 1+2+3+4+...+99+100
=100x101/2
=10100/2
=5050
3) 1+2+3+4+...+999+1000
=1000x1001/2
=1001000/2
=500500
4) 1+2+3+4+...+9999+10000
=10000x10001/2
=100010000/2
=50005000
5) 1+2+3+4+...+9999+100000
=100000x100001/2
=10000100000/2
=5000050000
6) 1+2+3+4+...+99999+1000000
=1000000x1000001/2
=1000001000000/2
=500000500000
參考: myself
2007-12-15 1:07 am
1)(1+10)*10
--------------
2
=55

2)(1+100)*100
-----------------
2
=5050

3)(1+1000)*1000
--------------------
2
=500500

4)(1+10000)*10000
-------------------------
2
=50005000

5)(1+100000)*100000
----------------------------
2
=5000050000

6)(1+1000000)*1000000
-------------------------------
2
=500000500000
2007-12-15 1:04 am
1) 1+9=10
2+8=10
3+7=10
4+6=10
10+5=15
10+10+10+10+15=55
2)一樣
3)一樣
4)一樣
5)一樣
6)一樣


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