求解三角聯立方程式...謝謝!!

2007-12-13 12:49 am
求解三角聯立方程式...謝謝!!
1. a = arctan[(Y3-y)/(X3-x)]-arctan[(Y2-y)/(X2-x)]
2. b = arctan[(Y2-y)/(X2-x)]-arctan[(Y1-y)/(X1-x)]

上式中a,b,X1,X2,X3,Y3,Y2,Y1為已知,求解x,y?

回答 (1)

2007-12-18 10:33 am
✔ 最佳答案
這題我相信你要很有耐性和很小心做先至得。

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參考: My Maths knowledge


收錄日期: 2021-04-23 12:38:51
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