關於指數函數

2007-12-10 1:56 am
1. 9(3^X+1) = 27^2x

2. 6^x+2-2(6^x+1)-12(6^x)=2

回答 (1)

2007-12-10 4:19 am
✔ 最佳答案
1. 9(3x+1) = 272x
9(3x‧31) = 272x
27(3x) = 272x
27(3x) = 36x
35x = 27
35x = 33
5x = 3
x = 3/5

2.6x+2﹣2(6x+1)﹣12(6x) = 2
36‧6x﹣2(6x‧6)﹣12(6x) = 2
36(6x)﹣12(6x)﹣12(6x) = 2
6x(36﹣12﹣12) = 2
6x(12) = 2
6x = 2/12
6x = 1/6
6x = 6-1
x = -1


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