1.501^2
2.2(x-y)^2+8(x-y)+8
急!!因式分解(F.2MATH)10分
2007-12-09 9:07 pm
回答 (2)
2007-12-11 3:36 am
✔ 最佳答案
1)501^2=(500+1)^2
=500^2+2(500)(1)+1^2
=250000+1000+1
=251001
2)2(x-y)^2+8(x-y)+8
=2[(x-y)^2+4(x-y)+4]
=2(x-y+2)(x-y+2)
=2(x-y+2)^2
參考: me
2007-12-10 8:08 pm
1. (500 + 1)^2
= 500^2+2(500x1)+1^2
=250000+1000+1
=251001
2. 2(x-y)^2+8(x-y)+8
= 2(x^2-y^2)+8x-8y+8
= 2x^2-2y^2+8x-8y+8
= 2[x^2-y^2+4x-4y+4]
= 500^2+2(500x1)+1^2
=250000+1000+1
=251001
2. 2(x-y)^2+8(x-y)+8
= 2(x^2-y^2)+8x-8y+8
= 2x^2-2y^2+8x-8y+8
= 2[x^2-y^2+4x-4y+4]
收錄日期: 2021-04-14 01:08:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071209000051KK01584