恆等式~~~
回答 (2)
✔ 最佳答案
23.(a)左方=x^2 +4x+4
比較同類項
A=1
-(A+B)=4
-A-B=4
-1-B=4
B=-5
(e)
144(y-x)^2 +96(x-y)+16
=144(x-y)^2 +96 (x-y)+16
=16 [9(x-y)^2+6(x-y)+1]
=16[3(x-y)+1]^2
=16(3x-3y+1)^2
23.(a)
A=1
-(A+B)=4
-A-B=4
-1-B=4
B=-5
(e)
144(y-x)^2 +96(x-y)+16
=144(x-y)^2 +96 (x-y)+16
=16 [9(x-y)^2+6(x-y)+1]
=16[3(x-y)+1]^2
=16(3x-3y+1)^2
參考: 做過的
收錄日期: 2021-04-29 19:40:30
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