Help maths

Let S be the side of the large metal cube
the surface area of the large metal cube = 6 x (S^2 ) = 6S^2

the volume of the small cube =S^3/64
the surface area of the small cube (S^3/64)^(1/3*2)(6) =6S^2/16
the total surface area of the small cubes to the large cube
= 64(6S^2)/16 : 6S^2
=4 (6S^2) :6S^2
=4:1 //