假設A=B
A^2=AB
A^2 -B^2= AB -B^2
(A -B) (A+B)=B(A -B)
A+B=B
2B=B
1+1=1????????
怎樣證實這題1+1=2係錯?
2007-12-07 9:46 am
回答 (2)
2007-12-07 9:58 am
✔ 最佳答案
你在一開始的假始已出了問題假設A=B
A^2=AB
A^2 -B^2= AB -B^2
(A -B) (A+B)=B(A -B) <-------------- 這裏 因為(A -B) = 0 所以是不可以相除的
A+B=B
2B=B
就我的知識層面
在數學界
暫時未有一個定義是給予 0 over 0 的
2007-12-07 10:00 am
the process from third process to fourth process is wrong.
because if you both side diveded by A-B, it means that diveded by 0, it is wrong.
because if you both side diveded by A-B, it means that diveded by 0, it is wrong.
收錄日期: 2021-04-13 14:39:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071207000051KK00273