F.4 附加數學 - 複角

2007-12-05 5:37 am
試求下列各式的值,答案保留根號:(1- 4)

1. sin195゚

2. cos(-105゚)

3. sec75゚

4. tan165゚

回答 (1)

2007-12-05 6:08 am
✔ 最佳答案
利用複角公式:
sin 15 = sin (45 - 30)
= sin 45 cos 30 - cos 45 sin 30
= (1/√2) (√3/2 - 1/2)
= (√3 - 1)/(2√2)
所以:
(1) sin 195 = sin (180 + 15)
= - sin 15
= (1 - √3)/(2√2)
(2) cos(-105゚) = cos 105゚
= cos (180゚ - 75゚)
= - cos 75゚
= - sin 15゚
= (1 - √3)/(2√2)
(3) sec 75゚= 1/cos 75゚
= 1/sin 15゚
= (2√2)/(√3 - 1)
= (2√2)(√3 + 1)/(√3 - 1)(√3 + 1)
= √2(√3 + 1)
(4) cos 15゚ = √(1 - sin2 15゚)
= √[1 - (1 - √3)2/8]
= (√3 + 1)/(2√2)
tan 165゚ = tan (180゚ - 15゚)
= - tan 15゚
= - sin 15゚/cos 15゚
= (1 - √3)/(1 + √3)
= (1 - √3)2/[(1 + √3)(1 - √3)]
= (4 - 2√3)/(-2)
= √3 - 2
參考: My Maths knowledge


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