math problems

2007-12-04 5:19 am
1. In △ABC, tan( A + B ) =
A. - tan C
B. tan C
C. - 1/tan C
D. 1/tan C

2.If the circle x^2 + y^2 + 3x + Ey + 9 = 0 touches the y-axis, then E =
A. 6 or -6
B. 9 or -9
C. 3
D. -3

回答 (2)

2007-12-04 5:31 am
✔ 最佳答案
1) tan ( A + B )
= tan ( 180* - C )
= - tan C [ Ans : A ]
2) Sub x = 0,
0^2 + y^2 + 3 ( 0 ) + Ey + 9 = 0
y^2 + Ey + 9 = 0
Since the circle touches the y - axis, so delta = 0,
E^2 - 4 ( 1 )( 9 ) = 0
E^2 = 36
E = 6 or -6 [ Ans : A ]

2007-12-03 21:58:50 補充:
For Q1, by angles sum of triangle, A + B + C = 180* and so A + B = 180* - CSince in 2nd quad, tan is -VE, tan ( 180* - C ) = - tan CFor Q2, touching y - axis means touching the line x = 0 and so by substitution, u can obtain y^2 + Ey + 9 = 0 and by the condition: delta = 0, E can be solved.
參考: My Maths Knowledge
2007-12-04 5:50 am
1. a+b+c=180
a+b=180-c
tan(a+b)=tan(180-c)
tan(a+b)= - tan c

thus.. the answer is (a).

2. because of " touches " this word......
delta=0
it touches the y-axis...........so x=0
y^2+Ey+9=0
delta=0
E^2-4(1)(9)=0
E^2-36=0
E^2=36
so....E=6 or-6

thus.. the answer is (a).


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