1)If 2cos^2A+sqrt3-2=2sinA-sqrt3 where 0<=A<=360, find the value of A.
2)It is given that 8sin^2B-9cos^2B=6sinBcosB
a)Find the value of tanB
b)If 0<=B<=360, find the value of B correct to the nearest 0.1 degree.
收錄日期: 2021-05-03 11:57:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071203000051KK03663