solve x^2(x-2)^2-2x(x-2)-3=0
答案係 -1,3,1(double root)
數學問題二 搵x
2007-12-03 8:13 am
回答 (1)
2007-12-03 8:42 am
✔ 最佳答案
x^2(x-2)^2-2x(x-2)-3=0[x(x-2)]^2-2x(x-2)-3=0
let a=x(x-2), a^2-2a-3=0
(a+1)(a-3)=0
a= -1or 3
a= -1
x(x-2)= -1
x^2-2x+1=0
(x-1)^2=0
x=1
a=3
x(x-2)=3
x^2-2x-3=0
(x+1)(x-3)=0
x= -1or 3
收錄日期: 2021-04-13 14:37:53
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https://hk.answers.yahoo.com/question/index?qid=20071203000051KK00059