1.x(6)-x(4)
=??
2.y²-x²-2xy-2y²
=??
初中數學.................
2007-12-03 6:07 am
回答 (6)
2007-12-03 7:42 am
✔ 最佳答案
1.x^6-x^4=x^6-x^4(x^6和x^4是異類項，不能相減)
2.y²-x²-2xy-2y²
=-x^2-2xy-y^2
=(-x-y)(x+y)
= -(x+y)(x+y)
= -(x+y)^2
參考: me
2007-12-04 10:24 am
1.x(6)-x(4)
=(x 2次-1)(x4次 )
=(x 2次-1)(x4次 )
2007-12-03 6:22 am
1 6x - 4x =2x or
6x - 4x = 0
2x= 0
x = 1/2
2 y²-x²-2xy-2y²
= -x²-2xy-y²
= (-x+y) (x-y)
6x - 4x = 0
2x= 0
x = 1/2
2 y²-x²-2xy-2y²
= -x²-2xy-y²
= (-x+y) (x-y)
2007-12-03 6:18 am
1. x(6)-x(4)=6x-4x
=2x
2. y²-x²-2xy-2y²=-x²-2xy-y²
=-(x²+2xy+y²)
=-(x+y)²
=2x
2. y²-x²-2xy-2y²=-x²-2xy-y²
=-(x²+2xy+y²)
=-(x+y)²
參考: 自己
2007-12-03 6:16 am
1)
6x - 4x
= 2x
2) y²-x²-2xy-2y²
= y² - 2y² - x² - 2xy
= y² - x² - 2xy
6x - 4x
= 2x
2) y²-x²-2xy-2y²
= y² - 2y² - x² - 2xy
= y² - x² - 2xy
2007-12-03 6:10 am
1.6x-4x
=2x
=2x
收錄日期: 2021-04-13 14:37:54
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