1)Sam uses a ruler with 0.1 cm marking to measure the length and the width of an Octopus Card.He finds that the length and the wdth are 8.5cm and 5.4 cm respectively.
a)Find the lower limit and upper limit of length and the width.
b)If these two measurements are used to calculate the area of the card,find the maximum absolute error of the area and the percentage error of the area(correct to 3 sig.fig)
中2mathz ,,5該幫幫忙
2007-12-02 7:20 am
回答 (2)
2007-12-02 7:41 am
✔ 最佳答案
a) maximum absolute error = 0.1/2 = 0.05 cmlower limit of length = 8.5 - 0.05
= 8.45
upper limit of length = 8.5 + 0.05
= 8.55
lower limit of length = 5.4 - 0.05
= 5.35
upper limit of length = 5.4 + 0.05
= 5.45
b) maximum absolute error = (0.1/2) * (0.1/2)= 0.025 cm
percentage error can not be found
2007-12-01 23:51:25 補充：
a) maximum absolute error of length = 0.1/2 = 0.05 cmb) maximum absolute error of area = (0.1/2) * (0.1/2)= 0.025 cm
2007-12-02 00:12:02 補充：
just the maximum absolute error can be foundmaximum absolute error = masimum relative error * 100% = maximum absolute error / measured value * 100% = 0.025 / ( 8.5 * 5.4 ) = 0.0545 %
2007-12-02 7:31 am
a, lower limit length:8.49cm
width:5.39cm
upper limit length :8.51cm
width:5.41
b,absolute error :0.01cm
percentage error :0.02%
width:5.39cm
upper limit length :8.51cm
width:5.41
b,absolute error :0.01cm
percentage error :0.02%
參考: my
收錄日期: 2021-04-13 14:37:24
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