i got taught this method much better than tree mmethod
2) 10 46 64 common factor (must be prime number)
5 23 32
do that until less than two of the three numbers can be simplidied, i.e. individual numbers are the numbers that could be factorised which is useless hence stop there.
SAY, the 23 was 25, then you can factorise the 5 and the 25 resulting in 1 and 5 respecitvely.
What you do now is multiply 2 , 5,23,32 together. which is 9890.
LCM is 7360
IF you were to find HCF, then you have to factorise a common factor out of ALL THE NUMBERS , NOT just some of them. if for the above example , the 23 was 25, you can just take out a 5 for the 5 and 25 because 32 is not divisible by 5. hence the HCF is 2