問一些maths??急.................help*
回答 (3)
2007-11-28 3:23 am
✔ 最佳答案
(A+B)x+A-6=x+4 For the x term,
A + B = 1 --- ( 1 )
For the constant term,
A - 6 = 4
A = 10 --- ( 2 )
Put ( 2 ) into ( 1 ),
10 + B = 1
B = -9
So A = 10, B = -9.
參考: My Maths Knowledge
2007-11-29 5:44 am
(A+B)x+A-6=x+4
For the x term,
A + B = 1 --- ( 1 )
For the constant term,
A - 6 = 4
A = 10 --- ( 2 )
Put ( 2 ) into ( 1 ),
10 + B = 1
B = -9
So A = 10, B = -9.
By compare:
Let (A+B)x=x
A+B=1-------1
Let A-6=4
therefore A=10
Sub A=10 into 1
therefore A+B=1
10+B=1
B= -9
A=10, B= -9
For the x term,
A + B = 1 --- ( 1 )
For the constant term,
A - 6 = 4
A = 10 --- ( 2 )
Put ( 2 ) into ( 1 ),
10 + B = 1
B = -9
So A = 10, B = -9.
By compare:
Let (A+B)x=x
A+B=1-------1
Let A-6=4
therefore A=10
Sub A=10 into 1
therefore A+B=1
10+B=1
B= -9
A=10, B= -9
參考: My Maths Knowledge
2007-11-28 3:23 am
By compare:
Let (A+B)x=x
A+B=1-------1
Let A-6=4
therefore A=10
Sub A=10 into 1
therefore A+B=1
10+B=1
B= -9
A=10, B= -9
Let (A+B)x=x
A+B=1-------1
Let A-6=4
therefore A=10
Sub A=10 into 1
therefore A+B=1
10+B=1
B= -9
A=10, B= -9
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