I have a 2nd order ODE in Laplace:
A(d^2u/dz^2) - su = -c
and have solved the general part:
u(s,z) = k1 + k2exp(SQRT(s/A)z) + k2exp-(SQRT(s/A)z)
with k1 the coefficient for the particular solution. How do I find k1?
finding a particular solution in a laplace equation?
2007-11-26 3:47 pm
回答 (2)
2007-11-26 4:10 pm
✔ 最佳答案
to find k1 , use method of undetermined coefficients: lets Up = k1 where k1 is arbitrary constant
subsitute into A(d^2u/dz^2) - su = -c
you get 0-s(k1)=-c
k1=c/s
參考: Myself, i just did a course on partial DEs ^^
2016-12-10 7:28 pm
Y(y(t))(s+3)^2 - 4s - 20 = -5/(s + 8) - a million / (s + 3) So Y(y(t)) = (-5/(s+8) - a million/(s+3) + 4s + 20)/(s+3)^2. This solves area a-c, from right here this is basically a team of fraction help and then looking the inverse.
收錄日期: 2021-05-03 14:20:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071126074706AAJqnFA