問數~關於三角函數~

👨🏻‍🏫 學術台數學

2007-11-26 9:57 am

已知cosθ+(cosθ)^2=1,則(sinθ)^2+(sinθ)^6+(sinθ)^8=?

回答 (2)

2007-11-26 10:06 am

✔ 最佳答案

cos+cos^2 = 1
cos= 1-cos^2 = sin^2

sin^2+sin^6+sin^8
=cos+cos^3+cos^4
=cos+cos^2(cos+cos^2)
=cos+cos^2 (As cos+cos^2=1)
=1 #

參考: me

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2007-11-27 12:27 am

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