Find the gradient?

gradient of any curve is given by its first derivative i.e. dy/dx.

dy/dx = [(-1)x^2 - 2x(2-x)] / (x^2)^2
= [x^2-4x]/x^4
= [x-4]/x^3
at the x axis, y = 0 , putting this into y = [ 2 - x ] / x^2 , we obtain x=2

put this value into dy/dx
-->dy/dx= [2-4]/(2)^3 = -1/4

y = [ 2 - x ] / x^2
when y = 0 . . . x = 2
gradient
y ' = [ x^2 (-1) - (2-x)2x ] / x^4
y ' = [ 2^2 (-1) - (2-2)2(2) ] / 2^4
y ' = - 4 / 16
y ' = - 1/4