中四函數~1題

2007-11-25 11:15 pm
己知f(x)=x²
(a) 求f(x)-f(x-1)

(b)求下列各式的值
(i) f(2)-f(1)
(ii) f(3)-f(2)
(iii) f(4)-f(3)
(iv) f(5)-f(4)

(c)由此, 求3+5+7+9+...+99的值

最重要是答第3題!!!!!!!!!!!!!

回答 (2)

2007-11-26 12:33 am
✔ 最佳答案
a) f ( x ) = x^2
f ( x ) - f ( x - 1 )
= x^2 - ( x - 1 )^2
= ( x + x - 1 )( x - x + 1 )
= 2x - 1
bi) f ( 2 ) - f ( 1 ) = 2^2 - 1^2 = 3
ii) f ( 3 ) - f ( 2 ) = 3^2 - 2^2 = 5
iii) f ( 4 ) - f ( 3 ) = 4^2 - 3^2 = 7
iv) f ( 5 ) - f ( 4 ) = 5^2 - 4^2 = 9
c) 3 + 5 + 7 + 9 + ... + 99
= ( 2^2 - 1^2 ) + ( 3^2 - 2^2 ) + ( 4^2 - 3^2 ) + ( 5^2 - 4^2 ) + ... + ( 50^2 - 49^2 )
= - 1^2 + 50^2
= 2499
參考: My Maths Knowledge
2007-11-30 1:20 am
c) 2499


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