要有埋部驟
把下列各多項式分解為因式
1.xy+bx+ay+ab
2.mp-np+mq-nq
3.ux+2vx+u+2v
4.mr+5m-nr-5n
有4條數唔識...
2007-11-25 9:37 pm
回答 (4)
2007-11-25 9:45 pm
✔ 最佳答案
1.xy+bx+ay+ab=x(b+y)+a(b+y)
=(b+y)(a+x)
2.mp-np+mq-nq
=p(m-n)+q(m-n)
=(m-n)(p+q)
3.ux+2vx+u+2v
=x(u+2v)+(u+2v)
=(u+2v)(x+1)
4.mr+5m-nr-5n
=m(5+r)-n(5+r)
=(5+r)(m-n)
2007-11-25 9:53 pm
1.
xy+bx+ay+ab
=x(y+b)+a(y+b)
=(x+a)(y+b)
xy+bx+ay+ab
=xy+ay+bx+ab
=y(x+a)+b(x+a)
=(y+b)(x+a)
2.mp-np+mq-nq
=p(m-n)+q(m-n)
=(p+q)(m-n)
3.ux+2vx+u+2v
=ux+u+2vx+2v
=u(x+1)+2v(x+1)
=(u+2v)(x+1)
4.mr+5m-nr-5n
=mr-nr+5m-5n
=r(m-n)+5(m-n)
=(r+5)(m-n)
xy+bx+ay+ab
=x(y+b)+a(y+b)
=(x+a)(y+b)
xy+bx+ay+ab
=xy+ay+bx+ab
=y(x+a)+b(x+a)
=(y+b)(x+a)
2.mp-np+mq-nq
=p(m-n)+q(m-n)
=(p+q)(m-n)
3.ux+2vx+u+2v
=ux+u+2vx+2v
=u(x+1)+2v(x+1)
=(u+2v)(x+1)
4.mr+5m-nr-5n
=mr-nr+5m-5n
=r(m-n)+5(m-n)
=(r+5)(m-n)
參考: 以上果幾條數,全部是本人的知識
2007-11-25 9:48 pm
xy+bx+ay+ab
= x(y+b)+a(y+b)
= (x+a)(y+b)
mp-np+mq-nq
= p(m-n)+q(m-n)
= (p+q)(m-n)
ux+2vx+u+2v
= ux+u+2vx+2v
= u(x+1)+2v(x+1)
= (u+2v)(X+1)
mr+5m-nr-5n
= m(r+5)-n(r+5)
= (m-n)(r+5)
= x(y+b)+a(y+b)
= (x+a)(y+b)
mp-np+mq-nq
= p(m-n)+q(m-n)
= (p+q)(m-n)
ux+2vx+u+2v
= ux+u+2vx+2v
= u(x+1)+2v(x+1)
= (u+2v)(X+1)
mr+5m-nr-5n
= m(r+5)-n(r+5)
= (m-n)(r+5)
參考: 自己 `
2007-11-25 9:45 pm
1)x(y+b)+a(y+b)
=(x+a)(y+b)
2) m(p+q)-n(p+q)
=(m-n)(p+q)
3) u(x+1)+2v(x+1)
=(u+2v)(x+1)
4)r(m-n)+5(m-n)
=(r+5)(m-n)
=(x+a)(y+b)
2) m(p+q)-n(p+q)
=(m-n)(p+q)
3) u(x+1)+2v(x+1)
=(u+2v)(x+1)
4)r(m-n)+5(m-n)
=(r+5)(m-n)
收錄日期: 2021-04-25 17:28:40
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https://hk.answers.yahoo.com/question/index?qid=20071125000051KK02040