要有部驟
把下列各多項式分解為因式
1 a+ab-1-b
2. 3a+3b-ax-bx
3. hk+3h+2k+6
4. x-2-xy+2y
有4條數唔識
2007-11-25 9:30 pm
回答 (2)
2007-11-25 9:43 pm
✔ 最佳答案
1. a+ab-1-b=a(1+b)-(1+b)
=(1+b)(a-1)
2. 3a+3b-ax-bx
=3(a+b)-x(a+b)
=(a+b)(3-x)
3. hk+3h+2k+6
=h(k+3)+2(k+3)
=(k+3)(h+2)
4. x-2-xy+2y
=(x+2)-y(x+2)
=(x+2)(1-y)
自己做ge...
唔知岩唔岩架..''
錯左唔好怪我呀!!!
參考: me
2007-11-25 9:47 pm
1)a+ab-1-b
=a(1+b)-(1+b)
=(a-1)(1+b)
2)3a+3b-ax-bx
=3(a+b)-x(a+b)
=(3-x)(a+b)
3)hk+3h+2k+6
=h(k+3)+2(k+3)
=(h+2)(k+3)
4)x-2-xy+2y
=(x-2)-y(x-2)
=(x-2)(1-y)
=a(1+b)-(1+b)
=(a-1)(1+b)
2)3a+3b-ax-bx
=3(a+b)-x(a+b)
=(3-x)(a+b)
3)hk+3h+2k+6
=h(k+3)+2(k+3)
=(h+2)(k+3)
4)x-2-xy+2y
=(x-2)-y(x-2)
=(x-2)(1-y)
收錄日期: 2021-04-23 17:26:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071125000051KK01996