✔ 最佳答案
H(Hydrogen)中只有一粒質子和一粒電子,所以ON沒有可能是2。
既然沒有可能是2,即H的ON只可能是0或1。
所以O(Oxygen)的ON是-1,
H--O--O--H
1 -1 -1 1
ON是要看其中的電子,所以先看H再看O。
因為出H2的standard electrode potential比出O2低,所以不會出H2。
H2O2(aq) → 2H+(aq) + O2(aq) + 2e-
希望解答到你 ^^
2007-12-01 18:18:14 補充:
Oxygen has an oxidation number of -2 in almost all of its compounds, exceptions are provided by the peroxides, 2- O-O-1 -1the oxidation numbers in the peroxide ion being calculated by splitting the shared pair equally between the two oxygen atoms.
2007-12-01 18:19:28 補充:
In all compounds, except ionic metallic hydrides, the oxidation number of hydrogen is +1
2007-12-01 18:20:22 補充:
In compounds containing more than two elements, the oxidation number of any one of them may have to be obtained by first assigning reasonable oxidation numbers to the other elements.
2007-12-01 18:20:49 補充:
In sulphuric acid, the most reasonable oxidation numbers for hydrogen and oxygen are +1 and -2, which gives sulphur an oxidation number of +6. ⊕ ㊀K MnO 4 O ㊀ ⊕ |K O-Mn-O | O+1 -2 => Mn:+6