redox reaction..urgent!!

2007-11-24 8:22 am
係H2O2入面
O既O.N.係-1
係由H=+1 prove出黎既
咁點解唔可以話H既O.N.係+2既?

點知邊個既O.N.先唔係fixed?

仲有條equation係咁:H2O2(aq) → 2H+(aq) + O2(aq) + 2e-
請問上面點知條equation唔係H2O2(aq) → H2(aq) + 2O(1-)(aq) + 2e-

回答 (1)

2007-11-24 5:20 pm
✔ 最佳答案
H(Hydrogen)中只有一粒質子和一粒電子,所以ON沒有可能是2。
既然沒有可能是2,即H的ON只可能是0或1。
所以O(Oxygen)的ON是-1,
H--O--O--H
1 -1 -1  1
ON是要看其中的電子,所以先看H再看O。
因為出H2的standard electrode potential比出O2低,所以不會出H2。
H2O2(aq) → 2H+(aq) + O2(aq) + 2e- 
希望解答到你 ^^

2007-12-01 18:18:14 補充:
Oxygen has an oxidation number of -2 in almost all of its compounds, exceptions are provided by the peroxides,    2- O-O-1 -1the oxidation numbers in the peroxide ion being calculated by splitting the shared pair equally between the two oxygen atoms.

2007-12-01 18:19:28 補充:
In all compounds, except ionic metallic hydrides, the oxidation number of hydrogen is +1

2007-12-01 18:20:22 補充:
In compounds containing more than two elements, the oxidation number of any one of them may have to be obtained by first assigning reasonable oxidation numbers to the other elements.

2007-12-01 18:20:49 補充:
In sulphuric acid, the most reasonable oxidation numbers for hydrogen and oxygen are +1 and -2, which gives sulphur an oxidation number of +6. ⊕     ㊀K  MnO      4     O ㊀ ⊕   |K  O-Mn-O     |     O+1   -2  => Mn:+6
參考: 自己


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