Evaluate
Q6 [nC1nC2+2(nC2)(nC3)+3(nC3)(nC4)+...+(n-1)(nC(n-1))(nCn)]
Q9 (nC0+nC1)(nC1+nC2)(...)[nC(n-1)+nCn]
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更新1:
stevieg_1023,你的回答的圖片未能正確顯示! 這些要即日用!
