數學題...急

2007-11-22 6:49 am
有一兩位數字,十位數字與個位數字之比為4:1,若將原數加2之和除以3,必等於數字倒換所成的新數,求原數?

請用一元一次方程式解答!!

回答 (2)

2007-11-22 7:11 am
✔ 最佳答案
設十位數字 為a
設個位數為b

十位數字與個位數字之比為4:1
=> a : b = 4 : 1
=> a = 4 x b

原數 是 (10 x a + b)

將原數加2之和除以3,必等於數字倒換所成的新數

=> ( (10xa + b) + 2 ) /3 = 10x b + a
=> 10a + b + 2 = 30b + 3a
=> 10 (4b) + b + 2 = 30 b + 3 (4b) ______ 因為 (a = 4 x b)
=> 41b + 2 = 42 b
ans: b = 2
and a = 4x b = 8

原數 : 82
2007-11-22 6:59 am
let the x be the unit digit, so 4x is the 10 unit digit
so the number is 4x * 10 + x = 41x
(41x + 2) /3 = 10x + 4x
41x + 2 = 42x
x=2
the number is 82
參考: myself


收錄日期: 2021-04-20 12:04:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071121000051KK04374

檢視 Wayback Machine 備份