B =
1 3
2 -1
det B = -1-6=-7
B^-1 = ??
inverse matrix
2007-11-22 6:19 am
回答 (1)
2007-11-22 9:20 pm
✔ 最佳答案
cofactor of B =[-1 -2]
[-3 1]
adjoint of B
= transpose of B =
[-1 -3]
[-2 1]
Therefore, B^-1 =
(1/det B) x (adjoint of B)
= (1/-7) x [-1 -3; -2 1] =
[1/7 3/7]
[2/7 -1/7]
If you have any problems, please feel free to ask.
參考: My Maths knowledge
收錄日期: 2021-04-13 14:32:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071121000051KK04222