Factorize the following expression
(x^2+1)^2 - 4x^2
一條勁難既數學題
2007-11-22 3:05 am
回答 (4)
2007-11-22 3:25 am
✔ 最佳答案
(x²+1)² - 4x²=x^4+2x²+1-4x²
=x^4-2x²+1 ／ =(x²-1)²
（是但一個）
2007-11-21 19:54:56 補充：
(x y)²=x² 2xy y²(x-y)²=x²-2xy y²E個係一條公式黎的
參考: 自己
2007-11-22 3:29 am
Factorize the following expression
(x^2+1)^2 - 4x^2
=[(x^2+1)- 2x][(x^2+1)+ 2x]
=(x^2- 2x+ 1)(x^2+2x+1)
=(x- 1)^2(x+1)^2
Yeah!!~
(x^2+1)^2 - 4x^2
=[(x^2+1)- 2x][(x^2+1)+ 2x]
=(x^2- 2x+ 1)(x^2+2x+1)
=(x- 1)^2(x+1)^2
Yeah!!~
參考: me
2007-11-22 3:29 am
(x^2+1)^2-4x^2
=(x^2+1-2X)(x^2+1+2x)
=(x^2-2x+1)(x^2+2x+1)
=(x-1)^2(x+1)^2
=(x^2+1-2X)(x^2+1+2x)
=(x^2-2x+1)(x^2+2x+1)
=(x-1)^2(x+1)^2
2007-11-22 3:09 am
(x^2+1)^2 - 4x^2
=[(x^2+1)- 2x][(x^2+1)+ 2x]
=(x^2- 2x+ 1)(x^2+2x+1)
=(x- 1)^2(x+1)^2
=[(x^2+1)- 2x][(x^2+1)+ 2x]
=(x^2- 2x+ 1)(x^2+2x+1)
=(x- 1)^2(x+1)^2
收錄日期: 2021-04-12 13:56:39
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