我想問以下咁既情況可以點轉?
可以解釋下?分母之中有分數好難搞...
1 / ( 40 / 3 )
x / { y - ( y ^ 2 / x ) }
maths...(10分)急~~~
2007-11-19 6:22 am
回答 (3)
2007-11-19 6:41 am
✔ 最佳答案
1 / ( 40 / 3 )= 1 ÷ 40/3
= 1 * 3/40
= 3/40
x / { y - ( y^2 / x ) }
= x ÷ { y - ( y^2 / x ) }
= x ÷ { xy / x - y^2 / x }
= x ÷ { (xy - y^2} / x }
= x * {x / (xy - y^2)}
= x^2 / y(x - y)
2007-11-18 22:44:42 補充：
注: (1) 乘用 * 符號代替(2) 你可以記下以下小tips:x / y / z = x ÷ (y / z) = x * (z / y) = xz / ya - b /c = ac / c - b / c = ac - b / c (因約簡後, ac /c = a)
2007-11-19 6:34 am
1 / ( 40 / 3 )
= 1* (3/40)
= 3/40
x / { y - ( y ^ 2 / x ) }
= x/{(xy - y^2)/x}
= x * {x/(xy-y^2)}
= x^2 /(xy-y^2)
= x^2 /[y(x-y)]
= 1* (3/40)
= 3/40
x / { y - ( y ^ 2 / x ) }
= x/{(xy - y^2)/x}
= x * {x/(xy-y^2)}
= x^2 /(xy-y^2)
= x^2 /[y(x-y)]
2007-11-19 6:31 am
1 / ( 40 / 3 ) =(40/3)
x / { y - ( y ^ 2 / x ) } =x / { ( y ^ 3 - x) / y ^ 2} = ( x y ^ 2 ) / ( y ^ 3 - x)
x / { y - ( y ^ 2 / x ) } =x / { ( y ^ 3 - x) / y ^ 2} = ( x y ^ 2 ) / ( y ^ 3 - x)
參考: me
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