✔ 最佳答案
The answer is B.
Consider the n consecutive integers are a, a+1, a+2, ..., a+ (n-1), where is a an integer.
Mean of n integers = (a+a+1+a+2+...+a+n-1)/n
= (na + 1 + 2 + ... + (n-1))/n
= [na + (n-1)n/2] / n
= [a + (n-1)/2]
Hence only when n is an odd integer, (n-1)/2 could be an integer, i.e. a + (n-1)/2 is also an integer.