sin x ．cos x =0.25
0≤x≤2π
求x~
解方程~~
2007-11-17 11:34 pm
回答 (2)
2007-11-17 11:48 pm
✔ 最佳答案
sin x ．cos x =0.25(sin2x)/2=0.25
sin2x=0.5
2x=π/6 or 2x=5π/6
x=π/12 or x=5π/12
參考: myself
2007-11-17 11:56 pm
By Amaths method,
sin x ．cos x = 0.25
2 sin x ．cos x = 0.5
sin2x = 0.5
2x = π/6 or 2x = 5π/6
x = π/12 or x = 5π/12
sin x ．cos x = 0.25
2 sin x ．cos x = 0.5
sin2x = 0.5
2x = π/6 or 2x = 5π/6
x = π/12 or x = 5π/12
收錄日期: 2021-04-13 14:30:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071117000051KK02431