maths ch.5 7(c) 9(c) 11(c)(d)

呢本咪我用緊既數學書?
見計完沒耐,順便答埋你啦
我做既題目唔會有base既出現,所以7c你要同d log加番個4既base入去~
log2^(3/4) + (1/4)log8
= (3/4)log2 + (1/4)log2³
= 3/4log2 + 3/4log2
= 3/4(log4)
= 3/4
上面加番個4既base入去d log度~
log√27/2
= (1/2) log(27/2)
= 1/2 log 3³ - 1/2 log 2
= 3q/2 - p/2
= (p - 3q)/2
11c) [log x^(1/2) + 2 log x^(1/2)]/log x
= (1/2) log x + log x / log x
= (3/2)log x/log x
= 3/2
11d) (log√x + 4 log x)/9 log x²
= (1/2) log x + 4 log x / 18 log x
= 4.5 log x / 18 log x
= 1/4

7(c) Log4 [2^(3/4)] + 1/4 Log4 (8)
= 1/4 log (2^3) +1/4 log (8)
=2/4 log(8)
=1/2 log(4*2)
=1/2(log4 + log2)
=1/2[1 + log 4^(1/2)]
=1/2 + 1/4 log4
=1/2 + 1/4
=3/4 //

見唔到 9(c) & 11(c)(d)