LHS = cos (theta/2)
RHS = sin theta / 2sin(theta/2)
Prove a simple Amaths. thanks
2007-11-16 6:45 am
回答 (2)
2007-11-16 6:50 am
✔ 最佳答案
RHS = sin theta / [2sin(theta/2)]= [2sin (theta/2) cos (theta/2)]/[2sin(theta/2)]
= cos (theta/2)
= LHS
2007-11-17 12:04 am
rhs = sin theta / 2 sin(theta/2)
= 2 sin(theta/2) cos(theta/2) / 2 sin(theta/2)
= cos(theta/2) = lhs
= 2 sin(theta/2) cos(theta/2) / 2 sin(theta/2)
= cos(theta/2) = lhs
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https://hk.answers.yahoo.com/question/index?qid=20071115000051KK04371