中一數學,問一題!10分!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2007-11-16 2:47 am
題目:

7[2(x-3)+x]=4[1-3(x+2)]

要計算過程,快!

回答 (13)

2007-11-16 2:54 am
✔ 最佳答案
7[2(x-3)+x]=4[1-3(x+2)]
7[2x-6+x]=4[1-3x-6]
14x-42+7x=4-12x-24
21x-42=-12x-20
21x+12x=42-20
33x=22
x=1.5

2007-11-15 19:04:47 補充:
億分抱歉!正確答案是2/3...對不起

2007-11-15 19:09:19 補充:
richjenny2004:先乘除後加減!4[1-3(x 2)]的「1-3」(x 2)不是-2而是先計3(x 2)!

2007-11-15 19:11:32 補充:
rachel_ng1118:是-3乘6所以4[1-3(x 2)]不是4[1-3x 6]而是4[1-3x-6]要注意啊

2007-11-15 19:13:01 補充:
sppsf1c192:先ko小括才搞中括!!!

2007-11-15 19:42:52 補充:
Agape:請問如何從4[1-3(x 2)]計出4[-2]???!!十分不合理啊
2007-11-16 4:05 am
7[2(x-3)+x]=4[1-3(x+2)]
14x-42+7x=4-12x-24
33x=22
x=2/3//
想知邊ge係真正答案,就自己代ge數入去
當x=2/3
7[2(x-3)+x]=4[1-3(x+2)]
7[2(2/3-3)+2/3]=4[1-3(2/3+2)]....
2007-11-16 3:16 am
7[2(x-3)+x]=4[1-3(x+2)]
7(2x-6+x )=4(1-3x-6)
33x =22
x=2/3
參考: 自己
2007-11-16 3:14 am
7[2(x-3)+x]=4[1-3(x+2)]

7[2x-6+x]=4[1-3x-6]

14x-42+7x=4-12x-24

14x+12x+7x=4-24+42

33x=22

x=1.5
2007-11-16 3:07 am
7[2(x-3)+x]=4[1-3(x+2)]
7[2x-6+x =4[1-3x+6
7(3x-6)=4(7-3x)
21x-42=28-12x
21x+12x=28+42
33x=70
x=2又33分4
2007-11-16 3:06 am
7〔2x-6+x〕=4〔1-3x-6〕
7〔3x-6〕=4〔-3x-5〕
21x-42=-12x-20
21x+12x=-20+42
33x=22
x=22/33
x=2/3
2007-11-16 3:06 am
7[2(x-3)+x]=4[1-3(x+2)]

7[2x-6+x]=4[1-3x-6]

14x-42+7x=4-12x-24

21x-42=-12x-20

21x+12x=42-20

33x=22

x=1.5
2007-11-16 3:03 am
7[2(x-3)+x]=4[1-3(x+2)]
7[2x-6+x]=4[1-3x-6]
7(3x-6)=4(-3x-5)
21x-42=-12x-20
21x-12x=-20+42
9x=22
x=22/9
2007-11-16 2:56 am
7(2X-6+X)=4[-2(X+2)
21X-42=-8X-16
29X=26
X=26/29
2007-11-16 2:55 am
7[2(x-3)+x]=4[1-3(x+2)]
7(2x-6+x) =4(1-3x-6)
14x-42+7x=4-12x-24
14x+7x+12x = 4-24+42
33x =22
x=2/3


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