✔ 最佳答案
^2 = 二次
(x-3)^2-4x^2
=x^2-6x+9-4x^2
=-3x^2-6x+9
=-3(x^2+2x-3)
=-3(x-1)(x+3)
2007-11-14 22:17:45 補充:
Q ) 點解要做 (-x - 3)(3x - 3)= -3(x 3)(x - 1) ??A ) 因為 (x^2 2x-3) 仲可以繼續 factorize/ simplify 佢 用 cross method 就可以知道 (x^2 2x-3) )= (x 3)(x - 1)明唔明白?=]
2007-11-14 22:20:43 補充:
我上面 expand 左佢都 work或者可以用 A^2 - B^2 = (A+B)(A-B) 呢條式(x-3)^2-4x^2=(x-3)^2 - (2x)^2= (x-3+2x) ( x-3-2x)= (3x-3)(-x-3)= -3(x+3)(x-1)